An Overview

This Scenario is server-side controlled and it will depend on the type of server you are playing on in order to decide who has the edge. As you go through, you should notice that the “played” heroes count continues to drop with additional heroes being trained while the “won” heroes rise as training ticks down. For most of the following Scenario players, they will be focusing on heroes that are new to the spectrum, so if you are playing against the average player, you will have the advantage.

Overview

The goal of this Scenario is to explain the concept of Ranked Hero’s. No matter what you play this scenario for, your goal will always be to defeat the enemy and save their team. Unlike the traditional VS. Scenario, and even the Unranked Scenario, if one team has too many heroes, the other team can focus on neutralizing those heroes and control the match. In this Scenario, the value of the individual hero varies based on the time remaining before that hero’s ability tick. This is a very basic version, where the passive can be investigated in future versions.

Setup before the game

Create a hero team that you would like to play with.

• Max of 9 heroes
• Choose from the following list of heroes: Iron Man, The Human Torch, Steve Rogers, Jean Grey, Storm, Cyclops, Colossus, Phoenix, Magneto, Thanos and Thanatos. You will choose these heroes from the comic book character Movie Line-Up. All heroes have advantages and disadvantages that do not always agree with one another.
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  Null character messing with string

  I’m working on an iPhone app where I’m validating user input of a password. I’m thinking of handling the problem by just nulling out the incorrect characters in the user’s inputted password.
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  if I try the following…
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  // code here
  }
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  }

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  A:

  This is one example of when null-checkers are your friend. If you want to do this in a manner that doesn’t rely on a null-check (and you still end up checking if the char is a letter), you could do this:
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  String y = “0123456789abcdef”;

  for (int i = 0; i < x.length(); i++) {
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  if ('#' <= c && c <= '~') {
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  }
  }

  if (x.equals(y)) {
  // The passwords are the same.
  } else {
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  You could just write if (x.toLowerCase().equals(y.toLowerCase())) or alternatively, you could do string comparisons in the first place and use a case-insensitive comparison:

   

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  We are given a line bundle $\mathcal{O}_{\mathbb{P}^1}(n)$ with $n\geq 0$ and Frobenius normalization which is to say we have a global section $f$ such that the ideal of $f$ is generated by $f$ and $f^p$, which implies that $(f^p)^{(p-1)}=0$. We then obtain a trivial extension sheaf $\mathcal{O}_{\mathbb{P}^1}(n)\oplus \mathcal{O}_{\mathbb{P}^1}(n)$ and we have to show that this extension splits.
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