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Manish Soni Sulekh Gujarati Softwarebooksks

Manish Soni Sulekh Gujarati Softwarebooksks


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Using a constant in the lex rule

I am trying to handle the case in the lex file that a constant has the same value as one of the tokens. I am using Bison to parse a simple language and I have a defined a constant that can never be equal to a token (SFT). In the rule below, if the current token is equal to the constant (and not a number), I want to append “.SFT” to the current token.
set0(constant) : ‘0’+ {v0 = strip_trailing_zeroes(v0); return constant;};

This raises an error with Bison:
error: cannot use constant as delimiter in number.

I think this error message is because Bison tries to create a numeric constant. Any advice on how to accomplish what I am trying?

A:

I have a defined a constant that can never be equal to a token (SFT).

So, in your grammar, you have to define the beginning of the lexer rule with that “token”, or a special symbol like “END_OF_LEXER_RULE”, you cannot make a lexer rule like
set0(constant) : ‘0’+ {v0 = strip_trailing_zeroes(v0); return constant;};
: constant {
printf(“Set 0: %s
“, yytext);
}
;

… because the constant would not be an integer and would not be a character. (I suppose you could define the constant as a string literal, if you want to make a special symbol, but then you’d have to quote the string literal, which is much worse than the special symbol.)
Some versions of lex allow you to use a label instead of a symbol, which would be something like
set0(constant) : ‘0’+ {v0 = strip_trailing_zeroes(v0); return constant;};
: constant {
printf(“Set 0: %s
“, yytext);
}

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